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Monday, July 5, 2010

Who can help me understand the casino game

i know that i can bet the pass line, and wait for the come out roll to point then bet for a 6 or 8 as they come up more often, but there must be another strategy that i can use that can not defeat me, like a combination of three bets? please tell me some safe ways to bet the craps table and not lose my butt.
Mathematically, any bet you make on a craps table is -EV which means it has a negative expected value. You are correct that the pass line along with 6 and 8 are the most favorable for the player, however they are still -EV, and if you make any of those wagers over time, you cannot win. Expected value can be calculated by finding the sum of all outcomes weighted by the likelyhood of each outcome.



Example: We are to flip a coin. Heads I pay you $1, Tails you pay me $2. Each outcome has a .5 chance, and my EV is calculated like this.



.5 (-$1) .5($2) = $0.50



Your EV should then be -$0.50 and looks like this.

.5($-2) .5($1) = -$0.50



While on any one flip, you may win or lose, on average you will lose $0.50 per flip, and the more times we flip the coin, the closer the actual amount won or lost will come to being exactly -$0.50.



Casino games work in exactly the same manner. By not paying you the proper odds when you win a wager, they ensure you cannot win over a large number of trials.
this is a good answer, but slightly incorrect. There are 2 bets on a craps table with EV. They are the don

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